12n^2+2n-1220=0

Solution for 12n^2+2n-1220=0 equation:

12n^2+2n-1220=0

a = 12; b = 2; c = -1220;
Δ = b2-4ac
Δ = 22-4·12·(-1220)
Δ = 58564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{58564}=242$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-242}{2*12}=\frac{-244}{24}
=-10+1/6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+242}{2*12}=\frac{240}{24}
=10
$